the side of a rectangle are in the ratio 3:2 if the area is 486 sq m find the cost of fencing is at 40 per meter
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Let the sides be 3X and 2X.
Given, area = 3X × 2X = 486
6X^2 = 486. X^2 = 81. X = 9.
Therefore sides are 27 m and 18 m.
Perimeter = 2 × (27 + 18) = 90 m.
Cost of fencing = 90 × 40 = 3600
Given, area = 3X × 2X = 486
6X^2 = 486. X^2 = 81. X = 9.
Therefore sides are 27 m and 18 m.
Perimeter = 2 × (27 + 18) = 90 m.
Cost of fencing = 90 × 40 = 3600
Answered by
13
Here is your solution
Given :-
The ratio of length and breadth of the given rectangle is 3:2,
Let the length and breadth be 3x and 2x .
as area of rectangle = length × breadth
=>486= 6x^2 =
=> 486/6 =x^2
=> x = 9
length = 3x =3×9=27
and breadth = 2x = 2×9=18
Thus the perimeter of the rectangle = 2 * (length + breadth) = 2 * (27 + 18) = 2 × 45 = 90.
Cost of fencing 40/meter=>40×90=Rs3600
hope it helps you
Given :-
The ratio of length and breadth of the given rectangle is 3:2,
Let the length and breadth be 3x and 2x .
as area of rectangle = length × breadth
=>486= 6x^2 =
=> 486/6 =x^2
=> x = 9
length = 3x =3×9=27
and breadth = 2x = 2×9=18
Thus the perimeter of the rectangle = 2 * (length + breadth) = 2 * (27 + 18) = 2 × 45 = 90.
Cost of fencing 40/meter=>40×90=Rs3600
hope it helps you
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