The side of a rectangle are of lengths(2x+1)cm and (3x+1)cm.The area if the rectangles is 117cm^2 .Find x and the perimeter of the rectangle
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Answered by
6
Hi...☺️
Here is your answer...✌️
GIVEN THAT,
The sides of rectangle are of length
(2x + 1) cm and (3x + 1) cm
★Longer side will be Length and Smaller side will be Breadth of rectangle
=> Length of Rectangle = (3x+1) cm
=> Breadth of Rectangle = (2x+1) cm
And,
Area of Rectangle = 117 cm²
Length×Breadth = 117
(3x+1) × (2x+1) = 117
6x²+3x+2x+1 = 117
6x²+5x+1-117 = 0
6x²+5x-116 = 0
6x²+29x-24x-116 = 0
x(6x+29)-4(6x+29) = 0
(x-4)(6x+29) = 0
=> x = 4 or x = -29/6
=> x = 4
[ Length and breadth cannot be negative ]
=> Length = 3x+1 = 3(4)+1 = 12+1
Length, L = 13 cm
=> Breadth = 2x+1 = 2(4)+1 = 8+1
Breadth, B = 9 cm
Now,
Perimeter of Rectangle = 2(L+B)
= 2(13+9)
= 2×22
= 44 cm
Answer : x = 4 , Perimeter = 44 cm
Here is your answer...✌️
GIVEN THAT,
The sides of rectangle are of length
(2x + 1) cm and (3x + 1) cm
★Longer side will be Length and Smaller side will be Breadth of rectangle
=> Length of Rectangle = (3x+1) cm
=> Breadth of Rectangle = (2x+1) cm
And,
Area of Rectangle = 117 cm²
Length×Breadth = 117
(3x+1) × (2x+1) = 117
6x²+3x+2x+1 = 117
6x²+5x+1-117 = 0
6x²+5x-116 = 0
6x²+29x-24x-116 = 0
x(6x+29)-4(6x+29) = 0
(x-4)(6x+29) = 0
=> x = 4 or x = -29/6
=> x = 4
[ Length and breadth cannot be negative ]
=> Length = 3x+1 = 3(4)+1 = 12+1
Length, L = 13 cm
=> Breadth = 2x+1 = 2(4)+1 = 8+1
Breadth, B = 9 cm
Now,
Perimeter of Rectangle = 2(L+B)
= 2(13+9)
= 2×22
= 44 cm
Answer : x = 4 , Perimeter = 44 cm
samamaaziz:
Thank you thank you so much
Answered by
4
Hi.
Here is your answer---
____________________
Let the Length and Breadth of a Rectangle be (2x + 1) and (3x + 1) respectively.
Area of the Rectangle = L × B
117 = (2x + 1)(3x + 1)
6x² + 2x + 3x + 1 = 117
6x² + 5x - 116 = 0
Splitting the Middle Term,
6x² + 29x - 24x - 116 = 0
x(6x + 29) - 4(6x + 29) = 0
By Zero Product Rule,
(x - 4)(6x + 29) = 0
x = 4 x = -29/6
Rejecting x = -29/6,
[since Length and Breadth of the Rectangle cannot be negative].
Thus, Value of x is 4.
Length = (2x + 1)
= 2 × 4 + 1
= 9 cm.
Breadth = (3x + 1)
= 3 × 4 + 1
= 13 cm.
For Perimeter of the Rectangle = 2( l + b)
= 2(9 + 13)
= 2 × 22
= 44 cm.
Thus, the Perimeter of the Rectangle be 44 cm.
___________________
Hope it helps.
Have a nice day.
Here is your answer---
____________________
Let the Length and Breadth of a Rectangle be (2x + 1) and (3x + 1) respectively.
Area of the Rectangle = L × B
117 = (2x + 1)(3x + 1)
6x² + 2x + 3x + 1 = 117
6x² + 5x - 116 = 0
Splitting the Middle Term,
6x² + 29x - 24x - 116 = 0
x(6x + 29) - 4(6x + 29) = 0
By Zero Product Rule,
(x - 4)(6x + 29) = 0
x = 4 x = -29/6
Rejecting x = -29/6,
[since Length and Breadth of the Rectangle cannot be negative].
Thus, Value of x is 4.
Length = (2x + 1)
= 2 × 4 + 1
= 9 cm.
Breadth = (3x + 1)
= 3 × 4 + 1
= 13 cm.
For Perimeter of the Rectangle = 2( l + b)
= 2(9 + 13)
= 2 × 22
= 44 cm.
Thus, the Perimeter of the Rectangle be 44 cm.
___________________
Hope it helps.
Have a nice day.
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