the side of a rectangle rectangular Park are in the ratio 4 is to 3 if its area is 1728 m square find the cost of its fencing at rupees 30 per metre
Answers
Answered by
10
Here is your solution
Given :-
The ratio of length and breadth of the given rectangle is 4:3
Let the length and breadth be 4x and 3x .
as area of rectangle = length × breadth
=>1728= 12x^2 =
=> 1728/12 =x^2
=> x^2 = 144
=>x=12
length = 4x =4×12=48
and breadth = 3x = 3×12=36
perimeter of the rectangle=2×(l+b)
=> 2 (48+36)
=>2×84
=>168m
Cost of fencing 30/meter=>30×168= Rs5040
hope it helps you
Given :-
The ratio of length and breadth of the given rectangle is 4:3
Let the length and breadth be 4x and 3x .
as area of rectangle = length × breadth
=>1728= 12x^2 =
=> 1728/12 =x^2
=> x^2 = 144
=>x=12
length = 4x =4×12=48
and breadth = 3x = 3×12=36
perimeter of the rectangle=2×(l+b)
=> 2 (48+36)
=>2×84
=>168m
Cost of fencing 30/meter=>30×168= Rs5040
hope it helps you
Answered by
49
Hey there!!!
Let 4x and 3x be the dimension of the rectangular park
According to the question -
L = 4x => 4 ×12 = 48
B = 3x => 3 × 12 = 36
Perimeter = 2( l+ b)
= 2 ( 48+36)
= 168
cost = rate × perimeter
= 30 × 168
= ₹ 5040
Hope this helps u !!!
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