Math, asked by Anushree3514, 1 year ago

the side of a rectangle rectangular Park are in the ratio 4 is to 3 if its area is 1728 m square find the cost of its fencing at rupees 30 per metre

Answers

Answered by SmãrtyMohït
10
Here is your solution

Given :-

The ratio of length and breadth of the given rectangle is 4:3

Let the length and breadth be 4x and 3x .

as area of rectangle = length × breadth

=>1728= 12x^2 =
=> 1728/12 =x^2
=> x^2 = 144
=>x=12

length = 4x =4×12=48
and breadth = 3x = 3×12=36

perimeter of the rectangle=2×(l+b)
=> 2 (48+36)
=>2×84
=>168m

Cost of fencing 30/meter=>30×168= Rs5040

hope it helps you
Answered by Anonymous
49

Hey there!!!

Let 4x and 3x be the dimension of the rectangular park

According to the question -

 = > 4x \times 3x \: = 1728 \\ = > {12} {x} ^{2} = 1728 \: {m}^{2} \\ = > {x}^{2} = 144 \\ = > x \: = \sqrt{144} \\ = > x = 12

L = 4x => 4 ×12 = 48

B = 3x => 3 × 12 = 36

Perimeter = 2( l+ b)

= 2 ( 48+36)

= 168

cost = rate × perimeter

= 30 × 168

= ₹ 5040

Hope this helps u !!!

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