the side of a rhombus is 10 cm and one of its diagonal is 12 cm
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Step-by-step explanation:
but what we have to find can u tell ?
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Step-by-step explanation:
The diagonals in a rhombus are perpendicular , and bisect each other
Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal
From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm
Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm
Area of rhombus is product of diagonal divided by 2, 16*12/2=96 sq.cm
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