Math, asked by afrah92, 9 months ago

the side of a rhombus is 10cm and the length of one
diagonals P. 12cm Find the length of other diagonal
the​

Answers

Answered by pathakdaksh1601
0

Step-by-step explanation:

answer in the uploaded photo

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Answered by nilesh102
11

Solution:-

let, Rhombus ABCD.

given:-

•The sides of a rhombus are 10cm and one diagonal is 12 cm .

let, DO = OB = ? , BD = ?

and AO = OC = 6cm, and AC = 12 cm

1) we know diagonal of rhombus are equally bisect each other and they are perpendicular to each other.

2) All sides of rhombus are equal.

so,

by Pythagoras theorem.

=> (AB)² = ( AO )² + ( OB )²

=> (10)² = (6)² + (OB)²

=> 100 = 36 + (OB)²

=> 100 - 36 = (OB)²

=> 64 = (OB)²

i.e.

=> (OB)² = 64

=> OB = √64

=> OB = 8 cm

so, we know

DO = OB = 8 cm

hence, BD = 16 cm

Area of rhombus = [(AC)×(BD)]/2

Area of rhombus = [ 12 × 16 ]/2

Area of rhombus = [192]/2

Area of rhombus= 96 cm²

Hence length of diagonal rhombus

is 16 cm and area of rhombus is

96 cm².

i hope it helps you.

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