Question

The side of a rhombus is 26cm and length of one of its diagnol is 48cm find the length of other daignol

Answer 1

Answer:

20 cm

DIAGONAL OF RHOMBUS BISECT EACH OTHER AT 90° .

SO , THE GIVEN DIAGONAL WILL BE 24 CM.

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.SO ,

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.SO ,26² = 24² + X²

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.SO ,26² = 24² + X²676 = 576 + X²

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.SO ,26² = 24² + X²676 = 576 + X²100 = X²

SO , THE GIVEN DIAGONAL WILL BE 24 CM.TWO BISECTED DIAGONAL AND WITH ONE SIDE WILL FORM A RIGHT ANGLE TRIANGLE.SO ,26² = 24² + X²676 = 576 + X²100 = X²10 = X

THE ANOTHER DIAGONAL WILL BE 2X = 2(10) = 20 CM