the side of a rhombus is 8 cm . if one of its diagonal measure 12 cm ,find the length of other diagonal and the area of the rhombus
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Answered by
2
Solution: we know that Diagonals of rhombus bisect each other...
So Apllying Pythagoras theorm..
8^2= 6^2+ x ^2
x^2= 25
x= 5.
so,required length of other diagonal is 5*2= 10 cm..
Area of rhombus= 1/2(d1*d2)
=> 1/2 ( 12 * 10 )
=> 60 sq. cm
I HOPE IT CLEARS YOUR DOUBTS
So Apllying Pythagoras theorm..
8^2= 6^2+ x ^2
x^2= 25
x= 5.
so,required length of other diagonal is 5*2= 10 cm..
Area of rhombus= 1/2(d1*d2)
=> 1/2 ( 12 * 10 )
=> 60 sq. cm
I HOPE IT CLEARS YOUR DOUBTS
Answered by
1
Hello!
Your Answer:
The first diagonal will be bisected by the second one at 90 degrees.
Therefore, side will act as a hypotenuse.
Hypotenuse = 8cm
8^2 =
⇒ 1/2 diagonal ^ 2 = 8 ^2 - 6^2 = 64 - 36 = 28
diagonal = 2 = 4
Area = 1/2 x diagonal1 x diagonal 2
1/2 x 12cm x 4
= 24 cm^2
I hope it helps you.
Please mark As Brainliest
Have A Great Day.
Your Answer:
The first diagonal will be bisected by the second one at 90 degrees.
Therefore, side will act as a hypotenuse.
Hypotenuse = 8cm
8^2 =
⇒ 1/2 diagonal ^ 2 = 8 ^2 - 6^2 = 64 - 36 = 28
diagonal = 2 = 4
Area = 1/2 x diagonal1 x diagonal 2
1/2 x 12cm x 4
= 24 cm^2
I hope it helps you.
Please mark As Brainliest
Have A Great Day.
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