The side of a rhombus whose diagonals are 16 cm and 12 cm in length, is
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10 cm
Step-by-step explanation:
Let the sides of rhombus be ABÇD
AC = 16 cm
BD = 12 cm
OA = 16/2 = 8 cm = OC
OB = 12/2 = 6 cm = OD
By Pythagoras theorem ,
P^2 + B^2 = H^2
OA^2 + OB^2 = AB^2
8^2 + 6^2 = AB^2
64 + 36 = AB^2
√100 = AB
AB = 10 cm
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