Math, asked by kushkumarsingh671, 11 months ago


The side of a rhombus whose diagonals are 16 cm and 12 cm in length, is

Answers

Answered by khushi7234
17

Answer:

this is your answer...

Attachments:
Answered by kunalmartolia1011
11

Answer:

10 cm

Step-by-step explanation:

Let the sides of rhombus be ABÇD

AC = 16 cm

BD = 12 cm

OA = 16/2 = 8 cm = OC

OB = 12/2 = 6 cm = OD

By Pythagoras theorem ,

P^2 + B^2 = H^2

OA^2 + OB^2 = AB^2

8^2 + 6^2 = AB^2

64 + 36 = AB^2

√100 = AB

AB = 10 cm

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