The side of a right angled triamgle are in A.P. show that they are in the ratio 3:4:5
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let the sides of the triangle be x, y, z
with z> x & y.
since the sides are in AP
y = x+d
z = x+2d where d is the common difference
By Pythagoras theorem
simplifying we get
solving we get
x:y:z = 3: 4: 5
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