Question

The side of a rohmbus is 10cm. The
Smaller diagonal i 1/3 s of the
greater diagonal
find the length of the greater
diugonal?​

Answer 1

Answer:

3

Step-by-step explanation:

Answer 2

the diagonals are AC and BD where BD>AC...

let,AO=OC=x

∴OB=√(10²-x²)=OD ❪as,diagonals of a rhombus bisect each other at right angles❫

now..BD=OB+OD=2√(10²-x²)

now...AC=AO+OC=2x

now.. according th the problem...

➤2√(10²-x²)=3×(2x)

➤√(10²-x²)=3x

➤(10²-x²)=9x²

➤10x²=100

➤X=√10

therefore...AC=2√10cm

and BD=2√(100-10)=2√90=6√10