The side of a sqare is increasing at a rate 0.2 cm/ s. rate of increase of pereter
Answers
Answered by
7
perimeter of square=4*side of square
let the length of square be a.
then its perimeter=4a.
if we differentiate it with respect to time...
rate of change in perimeter=4.da/dt.
we are given da/dt=0.2cm/s.
so rate of increase=4*0.2=0.8
let the length of square be a.
then its perimeter=4a.
if we differentiate it with respect to time...
rate of change in perimeter=4.da/dt.
we are given da/dt=0.2cm/s.
so rate of increase=4*0.2=0.8
Similar questions