Math, asked by shivachaubey9192, 10 months ago

The side of a square 8cm find the length of its diagonal in square root

Answers

Answered by rebornevils
0

Step-by-step explanation:

SIDE OF SQUARE IS 8 CM

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 =

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^2

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONAL

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONALHOPE IT HELPS

SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONALHOPE IT HELPS PLEASE MARK AS BRAINLIEST

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