The side of a square 8cm find the length of its diagonal in square root
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Step-by-step explanation:
SIDE OF SQUARE IS 8 CM
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 =
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^2
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONAL
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONALHOPE IT HELPS
SIDE OF SQUARE IS 8 CMACCORDING TO PYTHAGOREOUS THEORUM 8^2 + 8^2 = DIAGONAL^264+64= DIAGONAL^2128 = DIAGONAL^2√128 = DIAGONAL8√2 = DIAGONALHOPE IT HELPS PLEASE MARK AS BRAINLIEST