the side of a square ABCD is 5cm and another pqrs has perimeter is equal to 40 cm find the ratio of the perimeter of ABCD 2 perimeter of pqrs find the ratio of the area of ABCD 2 the area of pqrs
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Perimeter of ABCD= 4×side
4×5
20 cm
ratio of perimeter = 20/40=1/2 =
=1:2
area of ABCD=s×s
5×5=25
p of pqrs= 4×side
40=4×side
side =40/4
=10 cm
area=s×s=10×10=100
ratio=25/100=1/4=
=1:4
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