the side of a square are increased by 0.25 of their original length. what is the ratio of the new area to the old one
A.25:16
B.16:25
C.5:4
D.4:5
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Answer:
72 : 60 =
72
60
=
72÷12
60÷12
=
6
5
= 6 : 5 (HCF of 72 and 60 = 12)
Thus, the reduced form of 72 : 60 is 6 : 5.
(ii)
38 : 57 =
38
57
=
38÷19
57÷19
=
2
3
= 2 : 3 (HCF of 38 and 57 = 19)
Thus, the reduced form of 38 : 57 is 2 : 3.
(iii)
52 : 78 =
52
78
=
52÷26
78÷26
=
2
3
= 2 : 3 (HCF of 52 and 78 = 26)
Thus, the reduced form of 52 : 78 is 2 : 3.
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