Question

The side of a square is 10 cm. Find the area between inscribed and circumscribed circles of the square.

Answer 1

Radius of inner circle =1/2 the side of square=5

Radius of outer circle =1/2the diagonal of square=1/2*10√2=5√2

Area bw the circles =π(R^2-r^2)

π(50-25)

25π

Answer 2

Answer:

The area between inscribed and circumscribed circles of the square is 25π cm².

Step-by-step explanation:

The side of a square is 10 cm.

Using Pythagoras theorem, the length of the diagonal is

$d=\sqrt{10^2+10^2}=10\sqrt{2}$

Draw a circle inscribed and circumscribed.

The radius of inscribed 5 cm the radius of circumscribed circle is $5\sqrt{2}$.

The area between inscribed and circumscribed circles of the square is

$A=\pi R^2-\pi r^2$

$A=\pi \times (5\sqrt{2})^2-\pi \times 5^2$

$A=\pi \times 50-\pi \times 25$

$A=\pi \times (50-25)$

$A=25\pi$

Therefore the area between inscribed and circumscribed circles of the square is 25π cm².