Question

The side of a square is 12cm and the length and breadth of rectangle is 16cm and 10cm respectively. The area of rectangle is greater than the area of square by​

Answer 1

Answer:

Here you go ...............

Step-by-step explanation:

Length of side of square = 12cm

Length of rectangle = 16cm

Breadth of rectangle = 10cm

Area of square = side²

Area of rectangle = length x breadth

Area of square = 144cm²

Area of rectangle = 16x10 = 160cm²

area of rectangle - area of square = 160 - 144 = 16cm²

The area of rectangle is greater than area of square by 16cm²

Hope it helps you.

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Answer 2

$\huge\fcolorbox{red}{cyan}{16\:cm²}$

Step-by-step explanation:

First Lets Calculate The Area Of Square :-

• Side = 12 cm

$= > \bf \color{purple}{area = {side}^{2} } \\ = > \bf{lets \: put \: the \: values} \\ = > {12}^{2} \\ = > \boxed{144 \: {cm}^{2} }$

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Now Lets calculate The Area Of Rectangle :-

• Length = 16 cm

• Breadth = 10 cm

$\bf \color{orange}{area = length \times breadth} \\ = > \bf{lets \: put \: the \: values} \\ = > 16 \times 10 \\ = > \boxed{160 \: c {m}^{2} }$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Clearly Area Of Rectangle is greater than Area of Square and Now Lets Calcualte Their Difference :-

=>Area Of rectangle - Area of square

=>160 - 144

=>16

Thus Area Of Rectangle is greater than Area of square by 16 cm