Question

. The side of a square is 4 cm. The length of a rectangle is 8 cm and its width is 2 cm.
Find the perimeter and area of both figures.
​

Answer 1

≡QUESTION≡

The side of a square is 4 cm. The length of a rectangle is 8 cm and its width is 2 cm.  Find the perimeter and area of both figures.

​

                                                     

║⊕ANSWER⊕║

GIVEN

Length of the square = 4 cm

Area of the square = $side * side$

                               = $4 * 4$

                               = 16 cm²

Perimeter of the square = $4 * sides$

                                        = $4 * 4$

                                        = 16 cm

Length of rectangle = 8 cm

Breadth of rectangle = 2 cm

Area of the rectangle = $Length * Breadth$

                                    = $8 * 2$

                                    = 16 cm²

Perimeter of the rectangle = $2 * (length + breadth)$

                                             = $2 * (8+2)$

                                              = $2 * 10$

                                              = 20 cm

                                                       

Answer 2

Answer:

Hey mate! here is your answer

Side of a square = 4 cm

Perimeter = 4×Side or sum of all sides

= 4×4 = 16 cm

Area = (side)2 or side×Side

= 4×4 = 16 cm^2.

Length of a rectangle = 8 cm

Breadth or width = 2 cm

Perimeter = 2 (l+b)

= 2 (8+2)

= 2×10 = 20 cm.

Area = l×b

= 8×2 = 16 cm^2.

Hope it helps you DEAR

Plz follow me and mark as Brainliest! ❤

THANKS ❤