Question

The side of a square is 4 cm. The length of a rectangle is 8 cm and its width is 2 cm. find the perimeter and area of both figures.​

Answer 1

For square_ Perimeter=4×side

Therefore,4×4=16cm

Area=(side)^2

=(4)^2

=16cm^2

FOR RECTANGLE

PERIMETER

=2(l+b)

=2(10)

=20 cm

AREA

=L×B

=8×2

=16cm^2

Answer 2

$Perimeter \: \: of \: \: square = 4s = 16 \: cm \\ Perimeter \: \: of \: \: rectangle =2(8 + 2) = 20 \: cm$





$Area \: \: of \: \: square = {s}^{2} = 16 \: {cm}^{2} \\ Area \: \: of \: \: rectangle = lb = 16 \: {cm}^{2}$