the side of a square is 4m and it is converted into a rhombus whose major diagonal is 6m, find the other diagonal and area of rhombus
Answers
Answered by
12
Area of rhombus= Area of square.
Area of square= 4a^2
=4×4×4
=64m^2
Area of rhombus=64m^2
d1×d2×1/2=64
3×d2=64
d2=21.33m
Hope this will b helpful
Area of square= 4a^2
=4×4×4
=64m^2
Area of rhombus=64m^2
d1×d2×1/2=64
3×d2=64
d2=21.33m
Hope this will b helpful
AngelAngelina:
rhombus area formula
Answered by
6
Hey dear,
● Answer -
h = 5.29 m
A = 15.87 m^2
● Explanation -
# Given -
Let b & h be diagonals of a rhombus with side s.
s = 4 m
b = 6 m
# Solution -
s, b & h are related as -
b^2 + h^2 = 4s^2
6^2 + h^2 = 4×4^2
h^2 = 64 - 36
h^2 = 28
h = 5.29 m
Area of rhombus is given by -
A = 1/2 × b × h
A = 1/2 × 6 × 5.29
A = 15.87 m^2
Hope this helped you...
● Answer -
h = 5.29 m
A = 15.87 m^2
● Explanation -
# Given -
Let b & h be diagonals of a rhombus with side s.
s = 4 m
b = 6 m
# Solution -
s, b & h are related as -
b^2 + h^2 = 4s^2
6^2 + h^2 = 4×4^2
h^2 = 64 - 36
h^2 = 28
h = 5.29 m
Area of rhombus is given by -
A = 1/2 × b × h
A = 1/2 × 6 × 5.29
A = 15.87 m^2
Hope this helped you...
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