Question

the side of a square is 6 and the length of a rectangle is 6 and 4 cm find the area and perimeter of both the figures.​

Answer 1

Answer:

area of square will be side square ie 64 and the perimeter will be 16 on adding all sides

area of rectangle will be l*b ie 16 and perimeter will be 20

Answer 2

☆ ANSWER ☆:-

Let side of square be 6Cm.

Area of rectangle = 6 × 4.

Area of square = s²

s² = 6 × 4

s² = 2¹²

s = 2⁶

      = 64Cm

Difference of the perimeters =2(6+4)−4×64

                                               = 2(10)-4×64

= 20 - 4 × 64

                                               = 16 × 64

= 1,024Cm.