the side of a square is 6 cm find the ratio of the areas of circles inscribed and circumscribed about it
Attachments:
Answers
Answered by
5
Hope it will help u ......
Attachments:
Answered by
3
As the length of one side of square = 6cm
diagonal of the square = diameter of the big circle.
= √2 × 6 (as diagonal of a square = √2 a)
=6√2 cm
so, diameter of big circle = 6√2
therefore it's radius becomes 3√2
so, the area of big circle becomes π(3√2)(3√2) = 18π cm^2 ( πr^2 = area of a circle ).
Now in the case of the small circle,
diameter of the circle = distance between sides of the square = side of a square=6cm
therefore diameter of the small circle = 6cm
Therefore, the radius of the circle is 3cm.
so, it's area becomes π(3)(3)cm^2 =9π cm^2
Therefore their ratios become,
18π : 9π
= 2:1
diagonal of the square = diameter of the big circle.
= √2 × 6 (as diagonal of a square = √2 a)
=6√2 cm
so, diameter of big circle = 6√2
therefore it's radius becomes 3√2
so, the area of big circle becomes π(3√2)(3√2) = 18π cm^2 ( πr^2 = area of a circle ).
Now in the case of the small circle,
diameter of the circle = distance between sides of the square = side of a square=6cm
therefore diameter of the small circle = 6cm
Therefore, the radius of the circle is 3cm.
so, it's area becomes π(3)(3)cm^2 =9π cm^2
Therefore their ratios become,
18π : 9π
= 2:1
Similar questions