The side of a square is 75% of the diagonal of a rectangle whose sides are in the ratio 3: 4. Find the area of the square, if the perimeter of the rectangle is 28 meters.
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Let the dimensions be 3x and 4x
2(3x + 4x) = 28
or, x = 2
The sides are 6m and 8m
By Phythagoras Theorem,
Diagonal^2 = (6)^2 + (8)^2 = 100 = 10^2
Diagonal = 10m
Each side of square = 75×10/100 = 7.5m
2(3x + 4x) = 28
or, x = 2
The sides are 6m and 8m
By Phythagoras Theorem,
Diagonal^2 = (6)^2 + (8)^2 = 100 = 10^2
Diagonal = 10m
Each side of square = 75×10/100 = 7.5m
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