Question

The side of a square is increased by 20%. The percentage change in its area is

Answer 1

Answer:

Original side = 100x/100 = x

Now the side is increased by 20%

New side = 120 x / 100 = 1.2x

Original area = x²

New area = (1.2x)² = 1.44x²

Change in area = 1.44 x² - x² = 0.44 x²

Percentage change in area = change in area/original area ×100

= (0.44x² / x²) × 100

= 0.44 × 100

= 44%

Pls follow....

Answer 2

Step-by-step explanation:

Let the side of the square be 'x'.

We know that Area = x^2.

Given that side of a square is increased by 20%.

=> Length of each side = x + 20% of x = 120x/100 = (6/5)x

New area = (6x/5)^2 = (36x^2/25)

Now,

Increase in area = (36x^2/25) - x^2

                           = (36x^2 - 25x^2)/25

                           = 11x^2/25

So, the % increase in area = (11x^2/25) * (100/x^2)

= > 1100/25

= > 44.

Therefore, Area is increased by 44%.

Hope this helps!