Math, asked by kalpanapradhan, 1 year ago

The side of a square measures as 2.5 ft. If three of

these squares fit perfectly side by side in one rectangle,

then what are the minimum dimensions of the rectangle?

A) 6.5 ft and 2.5 ft

B) 7.5 ft and 3.5 ft

C) 5.5 ft and 2.5 ft

D) 7.5 ft and 2.5 f​

Answers

Answered by navneet2530
6

Answer:

(D) 7.5 ft. and 2.5 ft.....

Answered by SteffiPaul
0

Therefore the minimum dimensions of the rectangle are 7.5 ft and 2.5 ft.

Given:

The side of the square = a = 2.5 ft

3 such squares fit perfectly side by side in 1 rectangle.

To Find:

The minimum dimensions of the rectangle.

Solution:

The given question can be solved as shown below.

Given that,

The side of the square = a = 2.5 ft

3 such squares fit perfectly side by side in 1 rectangle.

If squares are placed side by side,

⇒ Then the length of the rectangle = L = side of 3 squares = a + a + a = 2.5 + 2.5 + 2.5 = 7.5 ft

⇒ The breadth of the rectangle = B = side of 1 square = a = 2.5 ft

Therefore the minimum dimensions of the rectangle are 7.5 ft and 2.5 ft.

#SPJ2

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