The side of a square s increasing at the rate of 4 cm/min at what rate is the perimeter increasing when side is 4 cm long.?
Answers
Answered by
0
Answer:
Rate of chage of perimeter=16 cm²/min
Step-by-step explanation:
let side is x
perimter p=4x
dp/dx=4 cm
dx/dt=4 cm/min
dp/dt=dp/dx * dx/dt=4*4=16 cm/min
rate of chage of perimeter=16 cm²/min
Similar questions