Question

The side of a square whose area is 64 sq. cm is:

a) 16 cm b) 8 cm c) 16 cm2

d) 8 cm2​

Answer 1

Answer:

b) 8 cm is the answer ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer 2

❍ Let's Consider the Side of Square is 64cm² .

$\dag\frak{\underline { As,\:We\:know\:that\::}}$

$\star\boxed {\pink{\sf{ Area _{(Square)} = Side \times Side \:or\:Side^{2}}}}$

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad:\implies \sf { 64= Side^{2} }$

$\qquad:\implies \sf { \sqrt{64}= Side }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Side = 8\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Side \:of\:Square \:is\:\bf{8\: cm}}}}$

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V E R I F I C A T I O N :

$\dag\frak{\underline { As,\:We\:know\:that\::}}$

$\star\boxed {\pink{\sf{ Area _{(Square)} = Side \times Side \:or\:Side^{2}}}}$

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad:\implies \sf { 64= 8^{2} }$

$\qquad:\implies \sf { 64cm^{2}= 64cm^{2} }$

⠀⠀⠀⠀⠀$\therefore {\underline {\bf{ Hence, \:Verified \:}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

• $\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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