Question

the side of a tectangle are in the ratio 7:2 and its perimeter is 108 cm .find its length and breadth ,and also find its area
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Answer 1

Answer:

Breadth = 12cm

Length =42cm

Area = 504cm

Step-by-step explanation:

Let Length and Breadth Be 7x and 2x respectively

Then,

2(l+b)=108

2(7x+2x)=108

18x=108

x=6

Breadth=2x=12

Length=7x=42

Area=l*b

=>12*42

=>504 cm^2

Answer 2

Answer:

length =42cm

breadth=12cm

Area = 504cm

Step-by-step explanation:

Side ratio = 7:2

let length be 7x and breadth be 2x

perimeter = 108cm

p = 2(l+b)

108cm = 2(7x+2x)

108cm = 18x

108/18 = x

6 = x

Therefore, length = 7x = 7×6=42cm

breadth= 2x = 2×6=12cm

Now,

Area= l×b

Area = 42×12

Area = 504cm

HOPE IT HELPED!!

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