Question

The side of a triangle are 25cm, 39cm and 56cm. Find the altitude to the longest side.
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Answer 1

Answer:

A=hbb

2

A=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving forhb

hb=﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4

2b=﹣254+2·(25·39)2+2·(25·56)2﹣394+2·(39·56)2﹣564

2·39≈21.53846cm

Answer 2

Answer:

15 cm

Step-by-step explanation:

Area = √(p)(p-a)(p-b)(p-c)

p = (25 + 39 + 56) ÷ 2 = 60

Area = √(60)(60-25)(60-39)(60-56)

Area = √176400

Area = 420 cm²

For finding altitude,

Area = 1/2 x base x height

420 = 1/2 x 56 x height

420 = 28 x height

height = 420 ÷ 28

height = 15 cm

Hence, The altitude is 15 cm

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