the side of a triangle are 56 cm,60 cm,52 cm long find the area of triangle
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a=56
b=60
c=52
semi perimeter=a+b+c/2
=56+60+52/2
=168/2
=84
area of triangle =√(s-a)(s-b)(s-c)
s-a=84-56=28
s-b=84-60=24
s-c=84-52=32
=√28*24*32
=√2*2*2*2*2*2*2*2*2*2*3*7
=32√21
b=60
c=52
semi perimeter=a+b+c/2
=56+60+52/2
=168/2
=84
area of triangle =√(s-a)(s-b)(s-c)
s-a=84-56=28
s-b=84-60=24
s-c=84-52=32
=√28*24*32
=√2*2*2*2*2*2*2*2*2*2*3*7
=32√21
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