Question

.The side of a triangle are in the ratio of 25 : 14 : 12 and its perimeter is 510m. The greatest side of the triangle is (a) 120 m (b) 170 m (c) 250 m (d) 270 m​

Answer 1

Step-by-step explanation:

Answer:-

Given that:-

• The side of a triangle are in the ratio of 25 : 14 : 12
• Perimeter is 510 m
• The greatest side of the triangle is ?

Concept:-

Perimeter and Area

Let's Do!

We know that:-

$\boxed{\sf{Perimeter \ of \ Triangle = Side \ 1 + Side \ 2 + Side \ 3}}$

Placing the values, we get

$\boxed{\sf{510 = Side \ 1 + Side \ 2 + Side \ 3}}$

• Let the ratio constant be x.
• So, 3 sides are:-

1. 25x
2. 14x
3. 12x

$\boxed{\sf{510 = 25x + 14x + 12x}}$

$\sf{510 = 25x + 14x + 12x}$

$\sf{510 = 51x}$

$\sf{10 = x}$

• So, 3 sides are:-

1. 250 m
2. 140 m
3. 120 m

• So, 250 metre is the longest side (c)

Answer 2

Answer:

Concept - Here, is a triangle given in which sides are given in ratio and perimeter is given and we have to find the measure of greatest side.

$\huge \bf \: solution$

Let the side be x

$\small \fbox {perimeter \: = sum \: of \: all \: sides}$

$\sf \: 510 = 25x + 14x + 12x$

$\sf \: 510 = 51x$

$\sf \: \:x = \frac{510}{51}$

$\sf \: x \: = 10$

$\sf \therefore \: measure \: of \: largest \: side \: = 25(10) = 250$

$\huge \bf \longrightarrow\: option(C)$