Question

the side of a triangle are X square + 22 X square + 6 X + 7, 5 x square - 4 x + 15 what its perimeter ​

Answer 1

Answer:

28 X square+2X+22 it is the answer

Answer 2

LET ABC BE A TRIANGLE OF SIDES

AB = $X^{2} + 22$

BC = $X^{2} + 6X + 7$

CA = $5X^{2} - 4X + 15$

PERIMETER OF ΔABC = AB + BC + CA

                                     = $X^{2} + 22$ + $X^{2} + 6X + 7$ + $5X^{2} - 4X + 15$

                                     = $7X^{2} + 2X + 44$