Math, asked by shilpapatil1903, 9 months ago

The side of a triangular field are 24m, 7m and 25m. find the number of triangular beds that can be made of sides 3m, 4m and 5m. ​

Answers

Answered by shankarpatil0392
14

Answer:

Given,

the sides of triangular field is

a=24m

b=7m

c=25m

semi perimeter=a+b+c/2

= 24+7+25/2

= 56/2

s=28m

using Heron's formula

area of triangle=√s(s-a)(s-b)(s-c)

=√28(28-24)(28-7)(28-25)

=√28×4×21×3

=√3×9×2×2×3×7×3

=√2×2×3×3×3×9×7

=√2×2×3×3×3×3×3×7

=√2×3×3×3×3×7

=√2×3×3×7

=√2×3×7

=42m2

side of bed=

a=3m

b=4m

c=5m

semi perimeter= a+b+c/2

=3+4+5/2

=12/2

s=6m

using Heron's formula

area of triangle=√s(s-a)(s-b)(s-c)

=√6(6-3)(6-4)(6-5)

=√6×3×2×1

=√3×2×3×2×1

=√2×2×3×3×1

=√2×3

=6m2

Hope this will help you

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Answered by ujjwalagole
1

Answer:

Step-by-step explanation:

The total area of the triangular field  found using heron's formula is 42m2.

The total area of the triangular bed  found using heron's formula is 6m2.

So number of triangular beds = Total area of field/ Total area of one triangular field.

Number of triangular beds = 42/6 = 7

Answer: Number of triangular beds =  7

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