The side of a triangular field are 24m, 7m and 25m. find the number of triangular beds that can be made of sides 3m, 4m and 5m.
Answers
Answer:
Given,
the sides of triangular field is
a=24m
b=7m
c=25m
semi perimeter=a+b+c/2
= 24+7+25/2
= 56/2
s=28m
using Heron's formula
area of triangle=√s(s-a)(s-b)(s-c)
=√28(28-24)(28-7)(28-25)
=√28×4×21×3
=√3×9×2×2×3×7×3
=√2×2×3×3×3×9×7
=√2×2×3×3×3×3×3×7
=√2×3×3×3×3×7
=√2×3×3×7
=√2×3×7
=42m2
side of bed=
a=3m
b=4m
c=5m
semi perimeter= a+b+c/2
=3+4+5/2
=12/2
s=6m
using Heron's formula
area of triangle=√s(s-a)(s-b)(s-c)
=√6(6-3)(6-4)(6-5)
=√6×3×2×1
=√3×2×3×2×1
=√2×2×3×3×1
=√2×3
=6m2
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Answer:
Step-by-step explanation:
The total area of the triangular field found using heron's formula is 42m2.
The total area of the triangular bed found using heron's formula is 6m2.
So number of triangular beds = Total area of field/ Total area of one triangular field.
Number of triangular beds = 42/6 = 7
Answer: Number of triangular beds = 7