Question

The side of a triangular park are 14 m, 17 m and 20 m. Find it's perimeter

Answer 1

Given:-

• Side of a triangular park are 14 m, 17 m and 20 m.

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To find:-

• Perimeter of triangular park.

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Solution:-

★Three sides are:-

• 14 m
• 17 m
• 20 m

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★Formula used:-

$\star{\boxed{\sf{\orange{Perimeter\: of\: triangle = sum\: of\: all\: sides}}}}$

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$\tt\longmapsto{Perimeter = A + B + C}$

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$\tt\longmapsto{Perimeter = 14 + 17 + 20}$

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$\tt\longmapsto{Perimeter = 31 + 20}$

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$\tt\longmapsto{\boxed{\red{Perimeter = 51\: m}}}$

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Hence,

• the perimeter of triangular park is 51 m.

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Diagram:-

$\setlength{\unitlength}{2.5mm}\begin{picture}(0,0)\linethickness{0.3mm}\qbezier(0,0)(0,0)(8,17)\qbezier(0,0)(0,0)(18,0)\qbezier(18,0)(18,0)(8,17)\put(8,17.8){\sf A}\put( - 1, - 1){\sf C}\put(18,-1){\sf B}\put(8, - 1.5){\sf 17 m}\put(15,8.1){\sf 14 m}\put( - 0,8.1){\sf 20 m}\end{picture}$

Answer 2

${\tt{\red{\underline{\underline{\huge{Answer= \: 51m}}}}}}$

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$\LARGE{\bf{\underline{\underline\color{purple}{Given:-}}}}$

$\sf\red{ Sides \: of \: triangular \: park \: }$

• $\sf\green{ First \: side \: = \: 14m \: }$
• $\sf\green{ Second \: side \: = \: 17m \: }$
• $\sf\green{ Third \: side \: = \: 20m \: }$

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$\LARGE{\bf{\underline{\underline\color{red}{Solution:-}}}}$

$\boxed{ \sf \blue{ Formula \: to \: find \: perimeter \: of \: triangle}}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Perimeter \: of \: Triangle \: = \: side \: + \: side \: + \: side }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: Perimeter \: of \: Triangle \: = \: 14m \: + \: 17m \: + \: 20m \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Perimeter \: of \: Triangle \: = \: 51m }} }\\ \\\end{gathered}\end{gathered}$

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$\boxed{ \sf \green{ So,\: the\: perimeter\: of \: Triangle\: = \: 51m}}$

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