Math, asked by Lakshya7909, 1 year ago

the side of a triangular part are 8m, 10m and 6m respectively .A small circular area of diameter 2m is to be left out and the remaining area is to be used for growing roses .How much area used for growing roses?

Answers

Answered by sucheth
4
The area of the triangle = (1/2)* base * height
= (1/2)* 8*6= 24 m^2

The area of circle = π(2)^2 = 4π= 12.56 m^2

The area used for growing roses = 24-12.56= 11.433 m^2


Hope this helps.

Anonymous: it's wrong.. kindly correct it. it's not given that it is a right angle triangle and height is this ir base is this.. u have to find the area by heron's formula
sucheth: Hi, The Length of the sides are given as 6,8,10.
sucheth: √6^2+8^2 =10.
sucheth: they are called traids.
sucheth: they form a right angle triangle.
sucheth: hope it cleared you confusion.
Anonymous: sorry.. i dunno
sucheth: No problem.
Answered by kritikak
1

Answer:

Semiperimeter of triangular park = (8+10+6)/2 = 12m.

Area of triangle heron's formula = Root {12(12-8)(12-10)(12-6)} = 24m2

Area of circle to be left out = Pie X (2/2)2 = 3.14m2

Area used for growing grasses = Total area - area to be left out

= 24m2 - 3.14m2 = 20.86m2

Step-by-step explanation:

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