Question

the side of an equaleteral triangle is 8cm, finds its area​

Answer 1

Answer:

Step-by-step explanation:

$\underline{\bold{Given:-}}$

Side of the Equilateral Triangle = 8 cm

$\underline{\bold{To \: Find:-}}$

Area of Triangle

$\underline{\bold{Formula \: to \: be \: used:-}}$

$\bf By \: \underline{Heron's \: Formula} \: i.e \: \sqrt{[s(s-a)(s-b)(s-c)]}$

$\underline{\bold{Solution:-}}$

$\sf Semiperimeter=\frac{8+8+8}{2} =\frac{24}{2} =12$

Now. Area of Triangle

$\sf\implies Area \: of \: Triangle= \sqrt{[s(s-a)(s-b)(s-c)]}$

$\sf\implies Area \: of \: Triangle=\sqrt{[12\times4\times4\times4]}$

$\bf\implies Area \: of \: Triangle=16\sqrt{3} \: cm^2$

Answer 2

$\huge\underline\purple{\mathcal Question:-}$ we have to find area of equilateral ∆.

$\huge\underline\blue{\sf Given:}$ :-- side is 8cm .

$\green{\bold{\underline{\underline{Step\:by\:step\:explanation:}}}}$

we know that, Area of equilateral ∆ with side a each is = $\large\red{\boxed{\sf \frac{ \sqrt{3} }{4} ( {a}^{2} )}}$

so, area of ∆ with side 8 will be ===

$\frac{ \sqrt{3} }{4} ( {8}^{2} ) = 16 \sqrt{3} \: cm^{2}$