Question

the side of an equilateral triangle is 20cm. two equal point chargers (+)3nC are placed at its two corners. what will be the amount of work done in bringing a (+)1nC test charge from infinity to third corner of the triangle.

Answer 1

Answer:

Let ABC be the equilateral triangle

Let +3nC charges are placed on corners of A and B

Let we have to bring +1nC charge from infinity to points C

to find potential at C

potential at C= potential due to A + potential due to B

=kqAAC+kqBBC

but qA=qB=+3nC

and AC=BC=20cm=0.2m

∴ potential at C=k×3nC0.2+k×3nC0.2

=9×1092×3×10−92×10−1

=54×1012

=270V

∵ Work done=potential × charge

∴ Work done =

W=270×1nC

=270×10−9J

=2.7×10−7J

Explanation:

Six pack body