the side of atriangle are in the ratio of 3:4:5and its perimeter is 24 find the area of a triangle
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let the ratio be x
3x+4x+5x=24
x,=2
now
side of triangle
ab=6
bc=8
ca=10
now
using using paythagores theorem
100=64+36
so it is right angle triagle of hypotenuse 10
so area of triangle
(1/2)*6*8
24square unit
Answered by
1
let the side be 3x,4x and 5x
3x+4x+5x=24
12x=24
x=24
3x=36
4x=48
5x=60
since (3,4,5)is a pythgorean triplet
therefore36,48,60 are sides of a right angled traingle
area of traingle = 1/2 × b ×h
1/2 x 36 x48
864 ans
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3x+4x+5x=24
12x=24
x=24
3x=36
4x=48
5x=60
since (3,4,5)is a pythgorean triplet
therefore36,48,60 are sides of a right angled traingle
area of traingle = 1/2 × b ×h
1/2 x 36 x48
864 ans
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