the side of one school is 3 cm longer than twice the side of second square . The difference in their areas is 144sq. find the side of the two square
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let
x = the length of the side of the first square
y = the length of the side of the second square
the side of one square is 3 cm longer than twice the side of the second square
x = 3 + 2y
the difference in their areas is 144 cm^2
x^2 - y^2 = 144
plug x = 3 + 2y into the last equation
(3 + 2y)^2 - y^2 = 144
by solving the equation we find and consider the positive roots (since the length of the side can not be a negative number)
y = 5 cm
x = 3 + 2*5
x = 13 cm
the sides of the two squares are 5 cm and 13 cm.
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