Question

The side of one square is 3 cm longer than twice of the second square the difference in their perimeter is 32 cm
find the sides of the two squares

Answer 1

$\sf Let \ the \ side\ of\ one \ square \ be \ {\bf x} \ and \ side\ of\ another\ square\ be \ {\bf (2x+3)}\ .\\\\\sf Difference \ in \ their \ perimeter = 32 \ cm\\\\\bf\boxed{\sf\bf PERIMETER\ OF \ SQUARE =4\times SIDE}\\\\\sf\longrightarrow 4(2x+3)-4x=32\\\\\sf\longrightarrow 8x+12-4x=32\\\\\sf\longrightarrow 8x-4x=32-12\\\\\sf\longrightarrow 4x=20\\\\\sf\longrightarrow x=20\div 4\\\\\sf\longrightarrow\bf x= 5\\\\\sf The \ sides \ of \ the \ squares \ are \ 5 \ cm \ and \ 13 \ cm \ .$

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