Question

THE SIDE OF ONE SQUARE IS 3 cm LONGER THAN TWICE THE SIDES OF THE SECOND SQUARE. THE DIFFERENCE IN THEIR AREAS IS 144 sq.cm . FIND THE SIDES OF THE TWO SQUARE​

Answer 1

Answer:

Step-by-step explanation:

let the side of second square be x  ∴area = x²

side of 1st sq. =2x +3  ∴area = (2x + 3)² = 4x² +12x+9

a/q......  4x² +12x+9 -x² =144

            3x² +12x+9 = 144

            3x² +12x=144 -9

                  x=..................................................

Answer 2

Answer:

Let the side of smaller square be X

So, side of bigger square = 2X + 3

Now, difference in area = 144 sq.cm.

(2X +3)² - X² = 144

4X² + 12X + 9 - X² = 144

3X² + 12X + 9 = 144

3X² + 12X - 135 = 0

3X² + 27X - 15X - 135 = 0

3X(X + 9) -15(X + 9) = 0

3X - 15 = 0. OR. X + 9 = 0

3X = 15. OR. X = -9

X = 5. OR. X = -9

But, side can't be negative.

So, X = 5

So,

Side of the smaller square

= 5 cms.

Side of the bigger square

= 2(5) + 3

= 13 cms.

Proof :-

(13)² - (5)² = 169 - 25

= 144

I hope this is helpful ☺