the side of one square is 3cm longer than twice the side of the 2nd square. the difference in their areas is 144sq cm. find the side of two squares
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Answered by
11
let
x = the length of the side of the first square
y = the length of the side of the second square
the side of one square is 3 cm longer than twice the side of the second square
x = 3 + 2y
the difference in their areas is 144 cm^2
plug x = 3 + 2y into the last equation
(3 + 2y)^2 - y^2 = 144
by solving the equation we find and consider the positive roots (since the length of the side can not be a negative number)
x = 3 + 2*5
x = 13 cm
the sides of the two squares are 5 cm and 13 cm.
priyanka000:
thanks
Answered by
13
area of 1st square is =( 3 + 2x )²
= 9 + 12x + 4x²
area of second square = (2x)²
= 4x²
difference:
9 + 12x + 4x² - 4x² = 144
12x = 135
x= 45/4
= 9 + 12x + 4x²
area of second square = (2x)²
= 4x²
difference:
9 + 12x + 4x² - 4x² = 144
12x = 135
x= 45/4
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