Question

The side of rectangle are 4x-y, 4x+3, 3x+1, x+6y find x and y and the area of the rectangle

Answer 1

Answer :

x=-19/2

y=-3

Explaination:

Yes that's right. You have to equate the expressions for widths and for the lengths, since left and right widths (and lengths) have the same dimensions.

You may rewrite the equation for y=3x+3÷6 as

y = (3x + 3)/6

And now you have an expression for y, we can substitute it to the other equation you got:

x = y + 1

x = (3x + 3)/6 + 1

And solve for x. After you got the value of x, you can solve for y.

That gives x = -19/2 and y = -3

So maybe you can clarify just what those expressions really mean

OR

if those are the lengths of the adjacent sides, then

4x-y = 4x+3

3x+1 = x+6y

That gives x = -19/2 and y = -3