Question

the side of rectangle are in the ratio 3:2. if the area is 486 sq m , find the cost of fencing in at rs.40 per metre

Answer 1

let the side be x
ratio of the sides are 3:2
so the sides are 3x and 2x
area of rectangle=l×b
486=3x×2x
6x=486
x^2=81
x=9
sides are 27 and 18
cost of fencing 1m^2=40
cost of fencing 486m^2=486×40
=972

cost of fencing = Rs.972
hope it helps uhh....

Answer 2

$hey \: there \: your \: answer \\ \\ let \: the \: sides \: be \: 3x \: and \: 2x \\ \\ so \\ \: \: \: \: 3x \times 2x = 486 {m}^{2} \\ \: \: \: \: 6 {x}^{2} = 486 \\ \: \: \: \: {x}^{2} = \frac{486}{6} \\ \: \: \: \: {x}^{2} = 81 \\ \: \: \: x = \sqrt{81} \\ \: \: \: \: x = 9 \\ \\ so \: \: 3x = 3 \times 9 = 27m \\ \: \: \: \: \: 2x = 2 \times 9 = 18m \\ \\ perimeter \: = 2(l + b) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(27 + 18) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 45 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 90m \\ \\ cost \: of \: fencing \: per \: metre = 40 \\ cost \: of \: fencing \: 90m = 90 \times 40 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = rupees \: 3600 \\ \\ \\ \\ please \: mark \: me \: brainlist$