The side of rectangular park are in the ratio 4 : 3. If its area is 2028 sq . m , find the cost of fencing it at 3rupees per metre
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let the length be 4x
and breadth be 3x
area of a rectangle = length ×breadth
2028 = 4x × 3x
12x^2 = 2028
x^2 = 2028/ 12
= 169
x = root (169)
= 13
so, length = 4x = 4× 13
= 52m
breadth = 3x= 3× 13
= 39m
as fencing is done on boundary we have to find the perimeter of the feild
= 2 (l+b)
= 2 (52+39)
= 2 (91)
=182m
cost of fencing per meter = Rs. 3
total cost =( 182)3
=Rs. 546.
and breadth be 3x
area of a rectangle = length ×breadth
2028 = 4x × 3x
12x^2 = 2028
x^2 = 2028/ 12
= 169
x = root (169)
= 13
so, length = 4x = 4× 13
= 52m
breadth = 3x= 3× 13
= 39m
as fencing is done on boundary we have to find the perimeter of the feild
= 2 (l+b)
= 2 (52+39)
= 2 (91)
=182m
cost of fencing per meter = Rs. 3
total cost =( 182)3
=Rs. 546.
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