the side of rectangular park qre in the ratio5:4 and it's area is 3380msquare. find the cost of fencing the park at the rate of 75 per metre square
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Let the length be 5x metre.
Let the breadth be 4x metre.
Area = 3380 sq metre.
By the problem,
5x×4x=3380
20x²=3380
x²=169
x=13
Hence, length = 13×5= 65 metre and breadth = 13×4= 52 metre.
Perimeter of the park = 2(65+52) = 234 metre.
Cost of fencing:
1 metre = ₹75
234 metre = ₹17550
Thank you!
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Read more on Brainly.in - https://brainly.in/question/6638120#readmore
Let the length be 5x metre.
Let the breadth be 4x metre.
Area = 3380 sq metre.
By the problem,
5x×4x=3380
20x²=3380
x²=169
x=13
Hence, length = 13×5= 65 metre and breadth = 13×4= 52 metre.
Perimeter of the park = 2(65+52) = 234 metre.
Cost of fencing:
1 metre = ₹75
234 metre = ₹17550
Thank you!
0.0
Read more on Brainly.in - https://brainly.in/question/6638120#readmore
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