the side of regular decagon is 5 3by5 cm find its perimeter
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HEY BUDDY .......
HERE IS UR ANSWER.........
FIRSTLY, A REGULAR DECAGON HAS 10 SIDES .
SO, PERIMETER OF REGULAR DECAGON = 10×side
AND SIDE = 53/5
THEREFORE, PERIMETER OF REGULAR DECAGON = 10×53/5 = 2×53 = 106cm
HOPE U UNDERSTAND BRO ✨✨
HERE IS UR ANSWER.........
FIRSTLY, A REGULAR DECAGON HAS 10 SIDES .
SO, PERIMETER OF REGULAR DECAGON = 10×side
AND SIDE = 53/5
THEREFORE, PERIMETER OF REGULAR DECAGON = 10×53/5 = 2×53 = 106cm
HOPE U UNDERSTAND BRO ✨✨
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