the side of rhombus is 5 cm and one diagonal measures 6 cm find area of rhombus
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1/2*d1*d2
1/2*6*6=18cm
1/2*6*6=18cm
yash307:
solve it
answer is 24 cm
Answered by
4
the diagonals of a rhombus
perpendicular bisectors of each other
so the side of rhombus, half parts of diagonal form right angled triangle
the side is hypotenuse
we can use Pythagorean theorem
let the other diagonal half part be x
5^2=3^2+x^2
25=9+x^2
x^2=16
x=4
x is half part so length of diagonal is 2x
2x=8
now by the formula
area of rhombus=1/2×product of diagonals
=1/2×6×8
=24cm^2
24 cm^2 is the area of rhombus
hope it helps you
perpendicular bisectors of each other
so the side of rhombus, half parts of diagonal form right angled triangle
the side is hypotenuse
we can use Pythagorean theorem
let the other diagonal half part be x
5^2=3^2+x^2
25=9+x^2
x^2=16
x=4
x is half part so length of diagonal is 2x
2x=8
now by the formula
area of rhombus=1/2×product of diagonals
=1/2×6×8
=24cm^2
24 cm^2 is the area of rhombus
hope it helps you
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