the side of squar field is 100 m long.if shiwam jogs around the field 4 time in a quarter hours, at what speed (in km/h) was he jogging.
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Answer:
21600km/h
Step-by-step explanation:
distance=100 x 4=400m
time=1/4 x 60=15
speed=d x t
=400m x 15s
=6000m/s
6000m/s=21600km/h
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