the side of square exceeds the side of another by 4cm .if the sum of the areas of the two sqare is 400 sq cm find the side of the sqare
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consider side of one square to be a and the other one to be a+4
a^2+(a+4)^2=400
a^2+a^2+8a+16=400
2a^2+8a-384
a^2+8a-192=0(dividing by 2)
by factorizing we will get 2 values 12 and -16 we neglect -16 as lenght cannot be negative therefore the a=12
a^2+(a+4)^2=400
a^2+a^2+8a+16=400
2a^2+8a-384
a^2+8a-192=0(dividing by 2)
by factorizing we will get 2 values 12 and -16 we neglect -16 as lenght cannot be negative therefore the a=12
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The side of the square is 6 cm
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