English, asked by javedrashida744, 4 months ago

The side of square is 4 cm The length of a rectangle is 8 cm and its width is 2 cm find the perimeter and area of both figure​

Answers

Answered by Anonymous
4

Square

Given:

  • Side of the square = 4 cm

To find:

  • Area and perimeter of square

Solution:

We know that,

\boxed {\mathfrak {\orange {Perimeter\ of\ square = 4s}}}

Where,

s denotes side of the square.

Perimeter = 4×4

\bigstar {\bf {\pink {Perimeter\ of\ square = 16\ cm}}}

Now,

\boxed {\mathfrak {\green {Area\ of\ square = s^{2}}}}

Area = 4²

\bigstar {\bf {\pink {Area\ of\ square = 16\ cm^{2}}}}

Area and Perimeter:

Area of the square is 16 cm² and perimeter of the square is 16 cm.

_____________________________________________

Rectangle

Given:

  • Length of the rectangle = 8 cm
  • Breadth of rectangle = 2 cm

To find:

  • Area and perimeter of rectangle.

Solution:

We know that,

\boxed {\mathfrak {\blue {Perimeter\ of\ rectangle = 2(l+b)}}}

Where,

l denotes Length

b denotes Breadth

Perimeter = 2(8+2)

Perimeter = 2×10

\bigstar {\bf {\pink {Perimeter\ of\ rectangle = 20\ cm}}}

Now,

\boxed {\mathfrak {\red {Area\ of\ rectangle = l \times b}}}

Area = 8×2

\bigstar {\bf {\pink {Area\ of\ rectangle = 16\ cm^{2}}}}

Area and Perimeter:

Area of the rectangle is 16 cm² and perimeter of the rectangle is 20 cm.

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